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in reply to Weird hash access problem

The scope of "$1" with respect to the regular expression is within the if block IIRC. Who knows what "$1" is outside of if block. Btw, you forgot "use warnings;" after "use strict;"

Jason L. Froebe

Blog, Tech Blog

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Re^2: Weird hash access problem
by ikegami (Patriarch) on May 26, 2011 at 18:33 UTC
    It's being used in the same block as the one in which it's set.
[reply]

      Interesting. I would have thought that the scope of what is in the if (...) would be only within the if (...) { } code block. The fact that it works doesn't mean the code should be written that way IMHO.

      Jason L. Froebe

      Blog, Tech Blog

[reply]

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