mysteries of regex substring matching

We all know that "In list context, a regex match returns a list of captured substrings." And, we also know "Numeric quantifiers express the number of times an atom may match. {n} means that a match must occur exactly n times." So can the numeric quantifier work with the captured substrings?

perl -E '$s = q[AAD34017837201D98AAED18778DEF993]; 
say length($s), " ", $s;
@m = $s =~ /(....)(....)(....)(....)(.+)/; 
say "", join("-",@m);'
# 32 AAD34017837201D98AAED18778DEF993
# AAD3-4017-8372-01D9-8AAED18778DEF993

In contrast, the following regex uses a numeric quantifier but does not work as above:

perl -E '$s = q[AAD34017837201D98AAED18778DEF993]; 
say length($s), " ", $s;
@m = $s =~ /(....){4}(.+)/; 
say "", join("-",@m);'
# 32 AAD34017837201D98AAED18778DEF993
# 01D9-8AAED18778DEF993

So, is there a way to use capture groups to match multiple times like separate groups does in the first example?

[haukex]

So, is there a way to use capture groups to match multiple times like separate groups does inthe first example?

Not really (Update: at least within a single regex, LanX already showed /g), unless you mess around with some of the more advanced regex features like maybe (?{})/(??{}). But before going down that route, this feels like an XY Problem to me; for example, for the task you show, unpack may be better, e.g. unpack("(A4)4A*","AAD34017837201D98AAED18778DEF993")

Minor edits.

[AnomalousMonk]

I think unpack is better for this as haukex has suggested, but here's a pure-regex solution:

Win8 Strawberry 5.8.9.5 (32)  Fri 01/15/2021 18:04:55
C:\@Work\Perl\monks
>perl -Mstrict -Mwarnings -MData::Dump=dd

my $s = q(AAAAbbbbCCCCddddXeeeeeeeeeeX);

my @caps = $s =~ m{ (?<! \A .{16}) \G .{4} | .* }xmsg;
dd \@caps;

^Z
["AAAA", "bbbb", "CCCC", "dddd", "XeeeeeeeeeeX", ""]

The trick is to have an unambiguous look-around anchor.

Update: Another variation:

Win8 Strawberry 5.8.9.5 (32)  Fri 01/15/2021 18:19:20
C:\@Work\Perl\monks
>perl -Mstrict -Mwarnings -MData::Dump=dd

my $s = q(AAAAbbbbCCCCddddXeeeeeeeeeeX);

my $n = 4;
my $m = 3;
my @caps = $s =~ m{ (?<! \A (?: .{$n}){$m}) \G .{$n} | .* }xmsg;
dd \@caps;

^Z
["AAAA", "bbbb", "CCCC", "ddddXeeeeeeeeeeX", ""]

[LanX]

Hi AnomalousMonk,

I'm sure we discussed this technique before, but I can't find it in the archives.

Do you remember a thread? :)

update

well I deciphered it in the meantime, it's not operating on match-groups but the /x /g ° modifier.

That'll repeat a search where the last match ended, and return all results in list context till it fails

  DB<139> p
0123456789abcdefghijklmnopqrstuvwxyz
  DB<139> x m{ .... }xg
0  0123
1  4567
2  '89ab'
3  'cdef'
4  'ghij'
5  'klmn'
6  'opqr'
7  'stuv'
8  'wxyz'
  DB<140>

with a negative look-behind (?<! ) we can filter out all matches after the initial 4

  DB<140> x m{ (?<! (?: .... ){4} ) .... }xg
0  0123
1  4567
2  '89ab'
3  'cdef'
  DB<141>

an or condition | helps matching after the fail.

  DB<142> x m{ (?<! (?: .... ){4} ) .... | .+ }xg
0  0123
1  4567
2  '89ab'
3  'cdef'
4  'ghijklmnopqrstuvwxyz'
  DB<143>

°) thanks AnomalousMonk++ for spotting :)

[LanX]

> So, is there a way to use capture groups to match multiple times like separate groups does in the first example?

It depends what your goal is.

If it's simply using a quantifier {4} the answer is no, because only the last match will be kept for the unique first group , that's why you get 01D9 at the end. Not a mystery.

But there are numerous workarounds I can think of.

Like

• using the /g modifier in a loop /(....)/g
• reading the last capture with embedded Perl code like /(....(?{print $1})){4}/

updates

• minor corrections
• links to perlretut

[LanX]

> using the /g modifier in a loop /(....)/g

demo:

  DB<53> $x = q[AAD34017837201D98AAED18778DEF993];

  DB<54> $x =~ m/(....)/g and say $1 for 1..4
AAD3
4017
8372
01D9

  DB<55>

[LanX]

> reading the last capture with embedded Perl code like /(....(?{print $1})){4}/

demo: (using /x for clarification)

  DB<66> $x = q[AAD34017837201D98AAED18778DEF993];

  DB<67> $x =~ m/(?: (....) (?{say $1}) ) {4} /x
AAD3
4017
8372
01D9

  DB<68>

update

I think this explains your "mystery", they all match but only the last one is kept in $1.

[LanX]

For completeness:

Another workaround was so trivial that I skipped it in my previous answer

You can build regexes from smaller ones with string interpolation

  DB<73> p $capt4 = '(....)' x 4
(....)(....)(....)(....)
  DB<74> x $x =~ m/ $capt4  (.+) /x
0  'AAD3'
1  4017
2  8372
3  '01D9'
4  '8AAED18778DEF993'
  DB<75>

I think that's the most readable solution.

[LanX]

Same approach, but as a one liner:

  
  DB<5> p
0123456789012345678901234567890123456789

  DB<5> x / @{[ '(....)' x4 ]} (.+) /x
0  0123
1  4567
2  8901
3  2345
4  678901234567890123456789
  DB<6>