in reply to Re: Getting the absolute path of a script, without PWD (update x2)
in thread Getting the shell's version of working directory, without PWD's help

Yup sorry, bad title. It's not the absolute path of the script I want, but the "current directory" in absolute path format. By the way, $0 and __FILE__ also do not seem to resolve symlinks so I'm guessing perl gets them from the shell also.
  • Comment on Re^2: Getting the absolute path of a script, without PWD (update)

Replies are listed 'Best First'.
Re^3: Getting the absolute path of a script, without PWD (update)
by LanX (Sage) on Jul 15, 2021 at 13:06 UTC
    You've replied to my update without reading it.

    getcwd and cwd are different and it's clearly documented

    Cheers Rolf
    (addicted to the Perl Programming Language :)
    Wikisyntax for the Monastery

      I've tested both cwd() and getcwd() before, and looked at the source. They both resolve symlinks. And the pwd and PWD variable from bash are not the same.

      UPDATE:Okay, so when we type pwd in bash by default we get the shell builtin, not the external Unix utility (/bin/pwd on my system). And the shell's pwd defaults to -L (logical) and we get the bash PWD. The external Unix utility defaults to -P (physical) which resolves symlinks. And if we run /bin/pwd -L, it still retrieves from PWD environment variable. Confirming my original question, we do need PWD and there's no way in Perl we can get the same version without PWD.