in reply to Re: (jeffa) Re: Why are closures cool, continued?
in thread Why are closures cool, continued?

That's a good example of using code refs, but it's not a closure. There are no private variables (unless I missed something there).

The anonymous routine (blessed or not) refers to a lexically-scoped variable in its enclosing scope. That lexically-scoped variable is magically kept alive (in the anonymous subroutine) after that enclosing scope has been exited. That is what makes an anonymous subroutine a closure.

sub makeAnonymousSub { sub { print "I am not a closure\n" } } sub makeClosure { my $x = shift; sub { print "I keep $x alive, thus I'm a closure\n" } }

Update: This is in agreement with perrin, btw. I'm just filling in some details...

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Re: Re: Re: (jeffa) Re: Why are closures cool, continued?
by perrin (Chancellor) on Jan 19, 2002 at 05:57 UTC
    Are we looking at the same thing? The example jeffa posted has this anonymous routine in it:
    print $foo->print_me(sub {ucfirst shift}), "\n";
    It's not a closure.