in reply to Re: Remove lowest number

First let's understand that I have no idea what I am doing and only a murky idea of what I want to do!

OK I'll give you the chomp I think that had something to do with an older version of this. See mostly I make Perl read logs and take data from different sources and shove it all together. But I don't do this everyday and as such I suck at it.

OK, so I thought:
```my @num = (8, 9, 3, 5, 1, 2, 6, 7) ;
my @all = sort { \$b <=> \$a } @num ;
thus:
```my \$num5 = 5 ;
my \$num4 = 4 ;
my \$num3 = 3 ;
my \$num2 = 2 ;

my @all = sort { \$b <=> \$a } \$num4, \$num2, \$num5, \$num3 ;
So when I was writing this code:
```my @d1s = sort { \$b <=> \$a } \$d61 ;
I thought I was sorting \$d61 and I thought it might be hard to get at the lowest number inside \$. Apparently I was wrong, but your code is over my head.
```\$sum += \$_ for @rolls;
Doesn't mean a lot to me. The whole \$_ thing confuses me.

UPDATE:

I really looked at this answer, suggestion and I started commenting things out to see which part of my code was really useless. Here's what is left:
```#! /usr/local/bin/perl
use diagnostics ;
use warnings ;
use strict ;
use List::Util qw (sum) ;        #not in the standard distro

my \$roll = 6 ;

until (\$roll == 0) {            #rolls the dice 6 times
\$roll -- ;

my @d61 = int(rand(5) + 2) ;    #6 sided die with no 1
my @d62 = int(rand(5) + 2) ;
my @d63 = int(rand(5) + 2) ;
my @d64 = int(rand(5) + 2) ;

my @all = sort                 #split line for looks
{ \$b <=> \$a } @d61, @d62, @d63, @d64 ;    #sorts rolls
#to prepare for
pop @all ;                    #pop removing
#the lowest roll
my \$sum = sum(@all) ;            #before adding

print "\n@all - \$sum\n" ;
}