This uses a trick I've thought about trying for several weeks, and finally got around to doing.  It turned out much better than I had expected.

After it was working the way I liked, I did a search through past obfuscations at Perlmonks to make sure nobody else had done this before.  The only other submission I found which uses crypt was this one, but its method is significantly different.

One of the nice things about using crypt is that running perl -MO=Deparse on it doesn't give anything away.

(I decided to create a signature based on the idea, too, which I'll use for the first time here).

@::=qw'79 11 34 69 41 27 2 4 4 2 5 4'; @::_=map{$x=pop@::;(crypt$_.' ',shift@::)=~/..(.{$x}).*/g} split/ /, 'writing Library. Building consider TO($FOO) *binary*'; map{print;/^[Hea]/ or print ' '}(@::_,',',$/)

@ARGV=split//,"/:L"; map{print substr crypt($_,ord pop),2,3}qw"PerlyouC READPIPE provides"

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Re: Crypto Japh
by secret (Beadle) on Dec 06, 2005 at 17:03 UTC
    veRy Nic3 !
    Here is my solution to this riddle ;)

      Very nice analysis++.

      The thing that took the most time was, of course, finding words (and combinations of word fragments) which gave the appropriate crypt results, since crypt is a one-way algorithm.  I was especially surprised when I found the fairly long (5-letter) string "anOTH".

      @ARGV=split//,"/:L"; map{print substr crypt($_,ord pop),2,3}qw"PerlyouC READPIPE provides"