reason why it doesn't work is that '> 98.0' is a string...not an operator and a value, unless you eval it. Therefore the "if" statement sees a list of two strings, and evaluates the list, which returns number of elements in list in scalar contenxt, which is equal to "2". "2" means TRUE in perl so the "if" always calls the sub. if the operator is always ">" then why on earth would you try to codify it into a variable? There's no need to be fancy, so just code it simple...and we can all go home :)
if($consumption > $threshold) {do something;}
the hardest line to type correctly is: stty erase ^H

In reply to Re: Using dynamic operators in an if() statement by aquarium
in thread Using dynamic operators in an if() statement by captkirk

Title:
Use:  <p> text here (a paragraph) </p>
and:  <code> code here </code>
to format your post; it's "PerlMonks-approved HTML":