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## Homework Statement

How far above the earth must an object be in order to lose 30% of its weight?

## Homework Equations

ma=Gm(Mearth)/r^2

a=v^2/r

v=2pir/T

## The Attempt at a Solution

I think the 30% lost weight would be the same as the earth's weight losing 30%. Therefore, I can put Mearth=(0.30)(6x10^24)

We have to solve for r to find the radius and then subtract it from the radius of the earth to find where this object is.

So rearranging the equation we get:

4pi^2r^3/T^2=0.30GMearth/r^2, where T=1 day and needs to be converted to seconds.

Finally, we rearrange to solve for r and get:

r=0.30GMearth/4pi^2