http://www.perlmonks.org?node_id=547134


in reply to Re: Counting the number of items returned by split without using a named array
in thread Counting the number of items returned by split without using a named array

a) You're right, I didnt want to know that

b) hm, I just wanted to catch spaces and tabs and thought \s+ most appropriate.

Never seen =()= in the perldoc before :-/
I.

  • Comment on Re^2: Counting the number of items returned by split without using a named array
  • Download Code

Replies are listed 'Best First'.
Re^3: Counting the number of items returned by split without using a named array
by blazar (Canon) on May 03, 2006 at 13:07 UTC

    Because it's not an operator of itself. It's an assignment to a list further piped into another assignment. It's just a means to create a list context. Others may find a better wording to describe it: possibly mine is not as technically accurate as it could be. Unfortunately as others already explained, it's not reliable to use it with split.

[reply]

In Section Seekers of Perl Wisdom