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in reply to Re: Puzzled by array
in thread Puzzled by array

Thanks trammell :)

But isn't @letters modified in the loop? Because when I have @new = @letters, @new stores the changed seqences.

Does that mean that \@letters always point to the original @letters?

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Re^3: Puzzled by array
by trammell (Priest) on Jul 06, 2005 at 17:10 UTC
    Sure, \@letters doesn't change. But when you leave the loop, @letters has been set back to r a c e--it looks like it hasn't changed, but it's really just been looped back to where it started.

    A few more print()'s would make this clear...

    Update: Fixed a typo, plus here's a modified version that makes it clearer what's happening (to me, anyhow):

    #!perl -l use strict; use warnings; my $some_word = 'race'; my @letters = split //, $some_word; my (@array1, @array2); for (1 .. @letters) { my @new = @letters; push (@array1, \@new); push (@array2, \@letters); my $myshift = shift @letters; push(@letters, $myshift); print "$_ : @letters : $array1[-1] : $array2[-1]" } print ''; print "array1 contains:"; foreach my $aref (@array1) { print "$aref => @$aref"; } print ''; print "array2 contains:"; foreach my $aref (@array2) { print "$aref => @$aref"; } __END__ 1 : a c e r : ARRAY(0x8067740) : ARRAY(0x805f380) 2 : c e r a : ARRAY(0x807c91c) : ARRAY(0x805f380) 3 : e r a c : ARRAY(0x807c8c8) : ARRAY(0x805f380) 4 : r a c e : ARRAY(0x807c820) : ARRAY(0x805f380) array1 contains: ARRAY(0x8067740) => r a c e ARRAY(0x807c91c) => a c e r ARRAY(0x807c8c8) => c e r a ARRAY(0x807c820) => e r a c array2 contains: ARRAY(0x805f380) => r a c e ARRAY(0x805f380) => r a c e ARRAY(0x805f380) => r a c e ARRAY(0x805f380) => r a c e

    Update 2: kiat asks: (W)hy doesn't \@letters point to the changed @letters inside the loop? That's just it--it does!

      Ah thanks :) But please bear with this nagging question: why doesn't \@letters point to the changed @letters inside the loop?

      Update

      Maybe I understand now...see modified code below:

      use strict; my $some_word = 'race'; my @letters = split //, $some_word; my (@array1, @array2); # Added this to show that the same $letter_ref is pushed into @array2 my $letters_ref = \@letters; for (1..@letters) { my @new = @letters; push (@array1, \@new); push (@array2, $letters_ref); my $myshift = shift @letters; push(@letters, $myshift); }
      Update 2

      My above reasoning was wrong. See my reply to neniro at Re^2: Puzzled by array