Directions: Using the digits 0 to 9, at most one time each, to make a true equation.

### Hint

How might you tell whether the digit 5 could be a coefficient? How might we tell whether digit 5 could be a constant?

### Answer

9(4a + 8b + 1 ) = 36a + 72b + 9

9(8a + 4b + 1 ) = 72a + 36b + 9

9(8a + 4b + 1 ) = 72a + 36b + 9

9(6a + 8b + 1 ) = 54a + 72b + 9

9(8a + 6b + 1 ) = 72a + 54b + 9

9(3a + 6b + 1 ) = 27a + 54b + 9

9(6a + 3b + 1 ) = 54a + 27b + 9

Source: Linda Cochran