Note that the code you've got is already fairly efficient.
Consider the following:
my $n = 0x80061861;
for (1..10_000_000) {
my $top14 = ( $n & 0xfffc0000 ) >> 18;
my $nxt6 = ( $n & 0x0003f000 ) >> 12;
my $mid6 = ( $n & 0x00000fc0 ) >> 6;
my $bot6 = ( $n & 0x0000003f );
# or replace the four lines above with:
#my ($top14, $nxt6, $mid6, $bot6) = (1,1,1,1);
}
Running as-is on my system takes 3.1s; using just the last line (which represents a baseline of creating, setting and freeing those four lexical vars), takes 1.9s. So any savings you make are likely to be less than that.
Dave.