Re: number comparison with a twist

[parv]

Below does not apply to other example data posted later.

---

What about doing the comparison after converting the string to integer AFTER removing the decimal point ($x =~ s,\.,, ; $x = int( $x ) ; $x == $y ? ... : ... ;)? Won't that work?

# Uses addition to 0 instead of int() to force conversion to number fr
+om string.

use strict; use warnings;

my @compare = ( [ 1990, '19.90' ],
                [ 465, '4.65' ]
              );

for my $pair ( @compare )
{
  my $from_api = $pair->[1];
  $from_api =~ s,\.,, ;
  $from_api += 0;

  printf "%0.f =?= %0.f  => %s\n",
     $from_api, 
     $pair->[0],
     ( $from_api == $pair->[0]
       ? 'same' : 'different'
     ) ;
}