`matrix = np.eye(3,3)` creates a ~~3D~~ 3x3 (thanks hv) matrix with 1's in the diagonal and 0 elsewhere.
(or load it from JSON).
- you mentioned
`points` being byte data, `np.frombuffer(points, dtype=np.float32)` converts it into a list of float32. And then it swaps the bytes - re: little endian etc.
`d.reshape(-1,6)` converts above list into a matrix with number of cols = 6 and any number of rows it can fit.
`d[:,2]` the 3rd column of matrix d
`pressure = (d[:,2] / pressure_norm) ** pressure_pow` create a `pressure` vector based on `d` where each item is divided by `pressure_norm` and then raise to `pressure_pow` power. (I guess ** is raising to a power)
`points.shape[0]` is the number of rows of `points` (remember it was reshaped to have 6 columns and any number of rows it fits).
`np.ones([points.shape[0],1])`, create a vector of 1s (i,e. a matrix of 1 column, that's the '1' in the expression) with as many rows as the reshaped `points` of the last bullet
- append that vector into
`points` hence increase the number of rows by 1 adding a vector of 1s at the end.
`points @ matrix.T` ~~I guess it transposes ~~`points` (rows become columns) it is multiplying the matrix 'points' by the transpose of 'matrix' (see NERDVANA's Re: Translating python math to Perl).
`points = points[:, :2]` get the 3rd column (0-based indexing) of the current `points`

my python is very limited so all above with caution. All the above can be done with pure perl but perhaps a dedicated module or PDL can be employed.

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