Re^4: positions of all occurrences of a substring in a string

retrieve the positions of all occurences...

Let me tell you something. Somethingsomething smells l
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16 != 17. Don't bump a decades old post with a wrong answer.

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Re^5: positions of all occurrences of a substring in a string by choroba (Cardinal) on Jun 18, 2024 at 06:30 UTC
All the other replies give the same answer. The first character is at position 0, not 1. `map{substr$_->[0],$_->[1]\|\|0,1}[\\|\|{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^ARGV,3]`	[reply] [d/l]
Re^5: positions of all occurrences of a substring in a string by harangzsolt33 (Chaplain) on Jun 20, 2024 at 04:36 UTC
First of all, I did not bump it up. You did. Or whoever "Anonymous Monk" is. I don't know who that is. It could be different people. Anonymous Monk replied to this decade old post on June 12. My post is dated June 13. Secondly, I did not give a wrong answer, because 16 is the correct answer. But if you think that 17 is the correct answer, then you just insert a "+1" into the code, and viola! it gives you the right answer. LOL :D	[reply]


No such thing as a small change
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