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regex issue

by Anonymous Monk
on Aug 03, 2016 at 12:39 UTC ( #1169091=perlquestion: print w/replies, xml ) Need Help??

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

Hi, i am working on my regexes, in this case backreferences. I found this code :

/\b(\w\w\w)\s\g1\b/;/

This code should find all three letter-doubles. Unfortunately i can't bring it to work, because there is little further explanation. i was hoping someone could give some useful comments about this line of code, maybe give a short example. I have added some code that i wrote , which finds all three-letter words and reports how many times each word occurs.Thanks

$term = 'Dit is het eerste het is niet het laatste Dit'; @woorden = split / /, $term; @let = grep (length($_)=3,@woorden); foreach(@let){ $aantal = $term =~ s/$_//g; if($aantal==0){next;} print "$_:"."$aantal\n"; };

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Re: regex issue
by AnomalousMonk (Bishop) on Aug 03, 2016 at 15:03 UTC

    First of all, I don't understand if you want all three-letter immediately repeated words, as your OPed regex
        /\b(\w\w\w)\s\g1\b/;/
    implies, or all three-letter words that are repeated anywhere else in the string, as your code implies.

    In the spirit of the second interpretation (and counting them) (requires Perl version 5.10+ for  \g-1 construct):

    c:\@Work\Perl>perl -wMstrict -MData::Dump -le "use 5.010; ;; my $term = 'Dit is het eerste het is xhetx xhet hetx niet het laatste + Dit'; ;; my $word = qr{ \b \w{3} \b }xms; ;; my %repeats; while ($term =~ m{ ($word) (?= .*? (?= $word) \g-1) }xmsg) { $repeats{$1}++; } ;; dd \%repeats; " { Dit => 1, het => 2 }
    Change the definition of  $word to whatever best suits your requirements. | See Update 3 below.

    Updates:

    1. Added info about 5.10+ requirement.
    2. BTW, the "regex"  /\b(\w\w\w)\s\g1\b/;/ doesn't actually compile. It looks like it might be a piece of something else, e.g., a substitution:
          s/\b(\w\w\w)\s\g1\b/;/
      (update: or maybe the / at the end is completely extraneous and the statement  /\b(\w\w\w)\s\g1\b/; was intended — that would work)
    3. When I wrote "Change the definition of  $word to whatever best suits your requirements" above, what I had in mind was that any  $word definition used in the context of the
          m{ ($word) (?= .*? (?= $word) \g-1) }xmsg
      match would be assured to match repeated words per my understanding of the OP. Not so, and it's easy to manufacture a counterexample. Of course, it's also easy to fix the counterexample to avoid the problem, but the fix requires knowledge of internal details of the  $word definition, and this is exactly what I was trying to avoid. In a further iteration, I can come up with a match regex that seems to fulfill all my (admittedly rather arbitrary) requirements, but it's not well tested and I don't really love it as I should. So as always, Caveat Programmor.


    Give a man a fish:  <%-{-{-{-<

      Why are you using ';;' every blank line? If you want a blank line, leave a blank line. If you want a comment, use the perl comment character, '#'.

      As Occam said: Entia non sunt multiplicanda praeter necessitatem.

        What you're seeing is a  perl -e " ... code ... " Windose command line padded out with spaces to emulate the appearance of multi-line source. The code comes from the Windoze clipboard. The original intent was to quickly cut/paste, possibly modify, and test posted code snippets, so I decided to eliminate blank lines. If I want to have something that looks like a blank line, "something" has to be there, and by convention, I use  ;; as that something.

        By the same token, because what's after the  -e switch is just a single string/line, any  # comment-to-end-of-line just clobbers the entire remainder of the line, even though the remainder appears multi-line. So, no comments.


        Give a man a fish:  <%-{-{-{-<

Re: regex issue
by Laurent_R (Canon) on Aug 03, 2016 at 15:14 UTC
    Please better define what you mean with "three letter-doubles". The two monks that responded previously understood something different, and I understood yet a third possibility.

    Please explain and/or provide an example.

      I meant all 3letter words that occur more than once.

        In that case:

        use strict; use warnings; my $term = 'Dit is het eerste het is niet het laatste Dit'; my @tlw = $term =~ /\b(\w{3})\b/g; # Now you have all the three-letter words, so count them my %seen = (); $seen{$_}++ for @tlw; for my $k (keys %seen) { print "$k occurs $seen{$k} times\n" if $seen{$k} > 1; }
Re: regex issue
by Anonymous Monk on Aug 03, 2016 at 12:49 UTC

    i made a mistake it should be length($_)==3.

      A slightly different approach can give you what you are looking for. By using a lookahead, you can do what you want.

      $term = 'Dit is het eerste het is niet het laatste Dit'; @captured = $term =~ /\b(\w\w\w)\b(?=.*\1\b)/g; print join ' ', @captured; _____________ Dit het het

      The \b are word boudaries (change from letter/number/underscore) to non-letter/number/underscore or vice-versa.

      The (?= looks forward for what comes after it, but remembers where it starts.

      The \1 is the same as your \g1 (I unfortunately have an older perl.)

      The g at the end means capture them all

      het appears twice since it is there three times

        Small correction, you missed a word-boundary assertion in the look-ahead. The regex should be:
        /\b(\w\w\w)\b(?=.*\b\1\b)/g
        Without the additional \b before \1, three-letter words that are trailing substrings of other words would also match.

        Thank you

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