Re^3: Case where '( shift @_ )[ 0, 0 ]' returns only one value?

I confirm these findings (on Perl running on Windows at least).

> berrybrew exec perl -le "@_ = qw( a b c ); @A = ( shift @_ )[ 0, 0 ]
+; print @A"

perl-5.28.1_64
==============
aa
perl-5.20.3_64
==============
aa
perl-5.18.4_64
==============
a
[download]

Comment on Re^3: Case where '( shift @_ )[ 0, 0 ]' returns only one value? Download Code

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Re^4: Case where '( shift @_ )[ 0, 0 ]' returns only one value?
by stevieb (Canon) on Jan 14, 2019 at 22:41 UTC

I was going to just edit my post after I got my perlbrew available issue sorted (which I did), but this warrants a new post.

In 5.10, it produces the result aa that is expected by OP:

spek@scelia ~/scratch $ perlbrew exec perl -le '@_ = qw( a b c ); @A =
+ ( shift @_ )[ 0, 0 ]; print @A'

perl-5.27.10
==========
aa


perl-5.26.1
==========
aa


perl-5.20.0
==========
aa


perl-5.18.4
==========
a


perl-5.10.1
==========
aa
[download]

Going full out, and am installing as many versions as I can to see where it "broke", where it "fixed" and where it "broke" again. Help desired.

Update: To further, on Unix, it "works" up to 5.12.5, from my testing so far, then goes awry:

spek@scelia ~/scratch $ perlbrew exec perl -le '@_ = qw( a b c ); @A =
+ ( shift @_ )[ 0, 0 ]; print @A'
perl-5.27.10
==========
aa


perl-5.26.1
==========
aa


perl-5.20.0
==========
aa


perl-5.18.4
==========
a


perl-5.16.0
==========
a


perl-5.14.4
==========
a


perl-5.12.5
==========
aa


perl-5.10.1
==========
aa
[download]

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