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Re^3: regex for strings with escaped quotes

by haukex (Bishop)
on Feb 12, 2019 at 15:55 UTC ( #1229819=note: print w/replies, xml ) Need Help??

in reply to Re^2: regex for strings with escaped quotes
in thread regex for strings with escaped quotes

$str =~ /(?:(?|(?:\")(?:[^\\\"]*(?:\\.[^\\\"]*)*)(?:\")))/;

It's missing the capture group that I added: /($RE{delimited}{-delim=>'"'})/

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Re^4: regex for strings with escaped quotes
by morgon (Priest) on Feb 12, 2019 at 16:35 UTC
    I don't quite understand...

    I do basically this:

    use Regexp::Common qw/delimited/; print $RE{delimited}{-delim=>'"'};
    And take what is printed.

    How can I get to a pure regex that works then?

      The regex is:


      which contains no capturing groups, hence $1 isn't populated. In my first bit of code, in the regex I added an extra set of parentheses, /($RE{delimited}{-delim=>'"'})/, so there is a capturing group there. That's the equivalent of:


      Alternatively, you can take the first regex above and just change the non-capturing group (?:...) that surrounds the entire expression into a capturing group:


      Or, since you said you wanted to capture the stuff between the quotes, change that non-capturing group into a capturing one:


      Plus, there's a bunch of simplifications that could be made to the first regex above anyway (really just removing unnecessary groups):

      / \" [^\\\"]* (?: \\. [^\\\"]* )* \" /x

      and just add capturing groups to that as needed.

        Ahh - I did not pay attention that you introducded a new capturing group by puttting the regex into an extra pair of brackets.

        Now it all makes sense - many thanks.

        I've never used Regexp::Common before but it seems to contain useful stuff - I see a bright future for it in my Go-Programs :-)

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