Re: Triangle Numbers

Incidentally, the formula for the nth triangular number is actually 1/2*n*(n+1) rather than the 5*n*(n+1) given above.

Now we *can* prove that the sum of two consecutive triangular numbers is a square number:

1/2*n*(n+1) + 1/2*(n+1)*(n+2)
=1/2*(n+1)*(2n+2)
=(n+1)^2

Thought I was going nuts for a second there :)

Comment on Re: Triangle Numbers

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Re: Re: Triangle Numbers by Anonymous Monk on Jul 26, 2002 at 01:40 UTC
You missed the decimal point in front of the 5.	[reply]
Re^3: Triangle Numbers by Anonymous Monk on Oct 03, 2004 at 16:20 UTC
which one is right	[reply]