Re: Re: comparing array elements

[Anonymous Monk]

the hash backfired! so i'm using a for loop. (little success so far) my comparison operator isn't working (both arrays contain 4- letter words) and i just need to determine which words are contained in the same position in each array.

thanks for helping!

for (my $i =0; $i < @forward_tets; $i++)   {

           if ($forward_tets[$i] =~ $reverse_tets[$i])  {
                      print "$forward_tets[$i] \t $reverse_tets[$i]\n"
+;
           }
}

[Abigail-II]

To compare two strings for equality, one uses eq, not =~ (although, if the words just contain letters, it would work too).

Abigail

[Anonymous Monk]

yep, but this loop seems to be comparing every position in the first array to every position in the second, not one at a time! How can I do this?

[Itatsumaki]

Why do you need two for-loops? Wouldn't one work?

my @array1 = ('test', 'text', 'next');
my @array2 = ('text', 'test', 'next');
for (my $i=0; $i < scalar(@array1); $i++) {
    if ($array1[$i] eq $array2[$i]) {
        print "$array1[$i] matches\n";
        }
    }

[Abigail-II]

How's that possible? You index both arrays with the same key.

Abigail