Depending on what you mean by acyclic paths, you might be able to. I would assume that if you can reach a point with a path of length 2, you don't want to count it again if you can reach it with a path of length 4. This situation might occur if these two points were a part of a path, and they could connect the short way--via two edges, or the long way--using 4 edges. In this case, just define an element wise subtraction operation and subtract all the shorter paths. Aka, calculate A^4 - A^3 - A^2 - A. You might be able to make this faster by leaving markers in your matrix. For example, if two points have been connected using a shorter path, place a -1 into the matrix and force your multiplication algorithm to copy it when the matrix is multiplied. I.e., -1 always maps to -1.
-
Are you posting in the right place? Check out Where do I post X? to know for sure.
-
Posts may use any of the Perl Monks Approved HTML tags. Currently these include the following:
<code> <a> <b> <big>
<blockquote> <br /> <dd>
<dl> <dt> <em> <font>
<h1> <h2> <h3> <h4>
<h5> <h6> <hr /> <i>
<li> <nbsp> <ol> <p>
<small> <strike> <strong>
<sub> <sup> <table>
<td> <th> <tr> <tt>
<u> <ul>
-
Snippets of code should be wrapped in
<code> tags not
<pre> tags. In fact, <pre>
tags should generally be avoided. If they must
be used, extreme care should be
taken to ensure that their contents do not
have long lines (<70 chars), in order to prevent
horizontal scrolling (and possible janitor
intervention).
-
Want more info? How to link
or How to display code and escape characters
are good places to start.
|