I use !!$x for this. Perl6 will give us ?$x, which ought to be clearer.
If I wanted to store the boolean back into
the same variable, I might prefer a
mutator: $x &&= 1.
However, there is a real difference:
sidhekin@blackbox:~$ perl
my ($x, $y) = (0, 0);
$x = $x && 1; # or $x &&= 1;
$y = !!$y;
print "\$x: '$x'\n\$y: '$y'\n";
__END__
$x: '0'
$y: ''
sidhekin@blackbox:~$
... something to be aware of :-)
print "Just another Perl ${\(trickster and hacker)},"
The Sidhekin proves Sidhe did it!
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