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Oh come off it.

sub list { return 1..5 } my ($a,$b,$c); my $n1 = ($a,$b,$c) = list(); my $n2 = my @x = ($a,$b,$c) = list(); print "$n1 ... $n2\n"; ---- 5 ... 3

When you have scalar = list = list, you will always get the count of items in the rightmost list in scalar. In your $n2 example, your array is getting three items from the list. It isn't a scalar, so it isn't getting the count. What else would be expected? The behavior that merlyn is referring to is the reason why you don't see the complete count in the scalar.

In reply to Re^3: List assignment in scalar context by !1
in thread List assignment in scalar context by Grimnebulin

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