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It's some Glib overloading. From muppet's explanation on the Perl/Gtk2 maillist:
> On 25/02/07, muppet <scott@asofyet.org> wrote: >> Well, TIMTOWDI, of course. :-) But, yes, the ">=" operator, which +is >> overloaded for Glib::Flags bitsets to mean the same as "&", which i +s >> "are all of the flags listed on the right hand side set in the left >> hand side?" is how i would write it. > > I can see that &, >= and * should be the same for this example. > >> The Glib::Flags operators are explained in the "This Is Now That" >> section of the Glib manpage. > > But in the manpage, it implies (to me at least) that there is a > difference between &, >= and *. Is there difference? For a boolean test, no. & and >= are implemented differently, but * and & are the same. The names (and operators) are derived from set theory, but you can also use any knowledge of binary logic operations + from C. (Warning: potentially redundant but intended-to-be complete information follows.) Glib.pm contains this: package Glib::Flags; use overload 'bool' => \&bool, '+' => \&union, '|' => \&union, '-' => \&sub, '>=' => \&ge, '==' => \&eq, 'eq' => \&eq, # eq for is_deeply in Test::More '*' => \&intersect, '&' => \&intersect, '/' => \&xor, '^' => \&xor, '@{}' => \&as_arrayref, '""' => sub { "[ @{$_[0]} ]" }, fallback => 1; Those subs are implemented essentially like this: bool := NOT NOT a if any of the bits in a are set, the expression evaluates to TR +UE union := a OR b the result contains all of the bits set in a and b that is, the result is the union of the two sets. the | mnemonic is for the C (and Perl) bitwise OR operator. the + mnemonic is for union of two sets -- you're adding them together. sub := a AND NOT b the result contains all the bits set in a minus the bits that were also on in b. this is subtracting the set of b from the set of a. the - mnemonic is awesome, because "a & ~b" is bizarre looking. ge := (a AND b) IS b the result is TRUE if the bits in b are on in a. other bits may be on in a, but they are ignored (by the AND). hence, this is true if the set of a is greater than or equal to the set of b. eq := a IS b the result is TRUE iff the same set of bits are on in both. intersect := a AND b the result contains all of the bits that are on in both a and b +. that is, it returns the intersection of sets a and b. the & mnemonic is the C (and Perl) bitwise AND operator. the * mnemonic is for the intersection of two sets. xor := a XOR b the result contains all of the bits that are on in either or both a and b. the bits that are on in both are not included; this is the exclusive or of the two sets. the ^ mnemonic is for the C (and Perl) bitwise XOR operator. All that said, i think the only ones i have ever used are the >= and bool operators.

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In reply to Re^2: Glib based forking server with root messaging by zentara
in thread Glib based forking server with root messaging by zentara

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