Is this what you are looking for?
When the following is run...
use URI;
$u1 = URI->new('http://www.comp.leeds.ac.uk/Perl/');
$u2 = URI->new('http://www.comp.leeds.ac.uk/Perl/filehandling.html');
print "u1.host=",$u1->host(),"\n";
print "u2.host=",$u2->host(),"\n";
if ($u1->host() eq $u2->host()) {
print "URL's host are the same\n";
}
else {
print "oops\n";
}
It produces the follwing output...
u1.host=www.comp.leeds.ac.uk
u2.host=www.comp.leeds.ac.uk
URL's host are the same
It doesn't use URI::URL, but I'm not sure that you need to.
Update:
The URI perldocs have a section on parsing URI's with a regex. Here's a cut of that section...
PARSING URIs WITH REGEXP
As an alternative to this module, the following (official) regular exp
+ression can be used to decode a URI:
my($scheme, $authority, $path, $query, $fragment) =
$uri =~ m|(?:([^:/?#]+):)?(?://([^/?#]*))?([^?#]*)(?:\?([^#]*))?(?:#
+(.*))?|;
The URI::Split module provide the function uri_split() as a readable a
+lternative.
Update:
To get around the problems of case you could use the URI canonical method like...
use URI;
$u1 = URI->new('http://www.comp.Leeds.ac.uk/Perl/')->canonical();
$u2 = URI->new('http://www.comp.leeds.ac.uk/Perl/filehandling.html')->
+canonical();
print "u1.host=",$u1->host(),"\n";
print "u2.host=",$u2->host(),"\n";
if ($u1->host() eq $u2->host()) {
print "URL's host are the same\n";
}
else {
print "oops\n";
}
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