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"Secret" operators

by cog (Parson)
on Jan 28, 2005 at 17:12 UTC ( #426037=perlmeditation: print w/replies, xml ) Need Help??

Besides the "secret eskimo greeting" and the "goatse" operator, which other "secret" operators have you heard of?

Secret eskimo greeting: }{

Goatse operator: =()=

Moved to Meditations by castaway

Replies are listed 'Best First'.
Re: "Secret" operators
by hardburn (Abbot) on Jan 28, 2005 at 17:48 UTC

    You may be familer with the spaceship operator already (<=>). What about the Super Star Destroyer operator?

    ${-} <=$vader=> ${-}

    Update: Now complete with TIE Intercepters!

    "There is no shame in being self-taught, only in not trying to learn in the first place." -- Atrus, Myst: The Book of D'ni.

      Ok, I tried it out and now I have some doubts...

      $a <=$b=> $c is equal to ( $a <= $b , $c), that one is easy...

      But what happens if I just use <=$something=>? Because printing that prints an equal sign, the contents of $something and another equal sign... I'm missing something, here...

        That's the <> operator. =$something= isn't a simple scalar, so it's equivalent to glob("=$something="). On the other hand, <$something> means readline($something). (For special weirdness, <$ something> is the same as glob($something).)

        See glob, readline and I/O Operators in perlop for details.

        I tried <=$vader=> (and also <==>), but they are both syntax errors. That's why I added the TIEs :)

        "There is no shame in being self-taught, only in not trying to learn in the first place." -- Atrus, Myst: The Book of D'ni.

Re: "Secret" operators
by TedYoung (Deacon) on Jan 29, 2005 at 04:30 UTC

    So why is it called the Goatse operator?

    Ted Young

    ($$<<$$=>$$<=>$$<=$$>>$$) always returns 1. :-)

      If you don't already know, then you really don't want to know. I really, really, really wish that I didn't know.

        Does it have something to do with that certain picture on that certain website... oh. Never mind.

        Ted Young

        ($$<<$$=>$$<=>$$<=$$>>$$) always returns 1. :-)
        Do tell, do tell :-)

        I know what it does, but I have no idea why it's named "goatse" (the eskimo thing is trivial, but this one doesn't seem to be).

        I heard it had been named after another operator... but in that case, which operator is that, and how come the name?

Re: "Secret" operators
by eyepopslikeamosquito (Bishop) on Mar 06, 2005 at 08:26 UTC
      Actually, *I* started that thread :-)
Re: "Secret" operators
by ambrus (Abbot) on Oct 20, 2014 at 10:38 UTC

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