Contributed by aaAzhyd
on Dec 18, 2000 at 22:33 UTC
Q&A
> files
Description: I have a file such as:
--
blah blah blah
blah blahblahblalh
oh yeah interesteing
no no no
nonnono
yes yes
--
I am wanting to read the file into an array spliting each element
by a blank line, such as @array[0] would be:
blah blah blah
blah blahblahblalh
Here is what I have tried doing:
open (LOG,"Messages.log");
while (<LOG>){
$string .= $_;
}
@array = split(/^\s*$/, $string);
and i have tried messing around with the regular expresion with no luck ..
Answer: Spliting a file into an array using blank lines as delimiter
contributed by davorg The secret is to change $/ to the
empty string. This will put Perl into
'paragraph mode', where the input record
separator is one or more blank lines. Something
like this:
#!/usr/bin/perl -w
use strict;
my @array;
{
local $/ = '';
@array = <DATA>;
}
print $array[0];
__END__
blah blah blah
blah blahblahblalh
oh yeah interesteing
no no no
nonnono
yes yes
| Answer: Spliting a file into an array using blank lines as delimiter
contributed by dsb your code would work but the pattern you have '$string' splitting on is no good. Right now you have it matching any line with 0 or more whitespaces at the beginning. That's every line. Try this:
open (LOG,"Messages.log");
while (<LOG>){
$string .= $_;
}
@array = split(/\n{2,}/, $string); # note the new pattern
|
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