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Re^2: Counting the number of items returned by split without using a named array

by blazar (Canon)
on May 03, 2006 at 11:07 UTC ( #547120=note: print w/replies, xml ) Need Help??


in reply to Re: Counting the number of items returned by split without using a named array
in thread Counting the number of items returned by split without using a named array

The =()= does work with matches:

$ perl -lpe '($_=()=/\s+/g)++' foo 1 bar baz 2 foo bar baz 3

But I would use split, especially with the smart behaviour provided by the default ' ' argument.

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Re^3: Counting the number of items returned by split without using a named array
by Hue-Bond (Priest) on May 03, 2006 at 13:38 UTC

    That fails when input has leading or trailing blanks:

    $ perl -lpe '($_=()=/\s+/g)++' ## leading foo bar 3 $ perl -lpe '($_=()=/\s+/g)++' ## trailing foo bar 3 $ perl -lpe '($_=()=/\s+/g)++' ## both foo bar 4 $ _

    It's better to count ocurrences of actual elements (\S+):

    $ perl -wle 'print scalar (()=/\S+/g) for "a b c", " a b c", "a b c ", + " a b c "' 3 3 3 3 $ _

    Anyway I prefer split too, like salva++'s 0e0 solution.

    --
    David Serrano

      I know. My entire point was not to maintain a counter manually a' la

      ++$cnt while $str =~ /\s+/g;

      Well done to point out about \S anyway, since one often forgets about \S, \D and \W.

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