x=i=1;p x+=i=x-i while+1
2006-11-17 Retitled by Arunbear, as per Monastery guidelines Original title: 'Fibonacci numbers - final shot - 24 chars'
Meh, if you don't have to use perl, you can do much better:
Re: Fibonacci numbers (again).
Update: let's put them under each other to see which one is longer.
1 2 3
ruby -e'x=i=1;p x+=i=x-i while+1'
It's also easy to shorten the ruby version by two characters
That's 33, not 24 (since omitting the first line gives a compile error).
If you want really small, try 4!
I'm sure f can be made way smaller than ruby.
Update: Downsized from 10
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