Re^2: ||= oddity


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Re^2: ||= oddity

by throop (Chaplain)

on May 28, 2008 at 22:45 UTC ( [id://688939]=note: print w/replies, xml )

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in reply to Re: ||= oddity
in thread ||= oddity

OK, once I knew what the answer was... it helped me find the answer in a manual. From 'Programming Perl, 2nd Edition', pp 92-93. It lists the assignment operators, including = and ||=, and says

List assignment may be done only with the plain assignment operator, =
+.  In a list context, list assignment returns the list of new values 
+just as scalar assignment does. ...
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