Re^2: Hard syntax error or disambiguable parsing?

(which you've written there misspelled as "for")

Rubbish! (Update: To quote you verbatim: "The words for and foreach have always been interchangable back to Perl version 0." )

absolutely wants to create a new local scalar variable

And yet, the first loop is legal.

Why bother replying?

Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.

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In the absence of evidence, opinion is indistinguishable from prejudice.

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Comment on Re^2: Hard syntax error or disambiguable parsing?

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Re^3: Hard syntax error or disambiguable parsing? by merlyn (Sage) on Jan 29, 2009 at 05:08 UTC
Sure, the words are interchangable, in the same way that you can omit $_ a lot. It's not as clear, and this is clearly a beginner, so I thought I'd bring clarity back. As for the second statement, I don't understand your complaint. The first loop does indeed create a new local scalar variable, as I said. -- Randal L. Schwartz, Perl hacker	[reply]
Re^4: Hard syntax error or disambiguable parsing? by pobocks (Chaplain) on Jan 29, 2009 at 05:38 UTC
It doesn't reuse the one created in the above line `my $i;`? Or do you mean uninitialized, rather than previously undeclared. Either way, why does a scalar member of an array not qualify? `for(split(" ","tsuJ rehtonA lreP rekcaH")){print reverse . " "}print "\b.\n";`	[reply] [d/l] [select]
Re^5: Hard syntax error or disambiguable parsing? by merlyn (Sage) on Jan 29, 2009 at 05:41 UTC
`my $i = 5; for $i (10..15) { } print "$i\n";` [download] prints 5. So clearly, the $i being iterated is not the $i from the my immediately above it. A scalar member of an array is not a simple scalar. By Larry's rule, it has to be a simple scalar. -- Randal L. Schwartz, Perl hacker	[reply] [d/l]
Re^6: Hard syntax error or disambiguable parsing? by pobocks (Chaplain) on Jan 29, 2009 at 05:53 UTC
Re^7: Hard syntax error or disambiguable parsing? by GrandFather (Saint) on Jan 29, 2009 at 06:05 UTC
Re^6: Hard syntax error or disambiguable parsing? by ack (Deacon) on Jan 29, 2009 at 16:05 UTC
Re^7: Hard syntax error or disambiguable parsing? by JavaFan (Canon) on Jan 29, 2009 at 16:20 UTC
Re^6: Hard syntax error or disambiguable parsing? by NateTut (Deacon) on Feb 13, 2009 at 21:26 UTC
Re^7: Hard syntax error or disambiguable parsing? by merlyn (Sage) on Feb 13, 2009 at 21:54 UTC
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Re^5: Hard syntax error or disambiguable parsing? by GrandFather (Saint) on Jan 29, 2009 at 06:02 UTC
The "variable" in a Perl for loop is aliased to each element that is being iterated over. It is effectively a symbolic place holder that is only valid within the scope of the loop body. However strict requires that variables are declared. Declaring the variable before the loop header makes it look like a normal variable - it ain't. Perl's payment curve coincides with its learning curve.	[reply]
Re^6: Hard syntax error or disambiguable parsing? by shmem (Chancellor) on Jan 29, 2009 at 10:15 UTC
Re^6: Hard syntax error or disambiguable parsing? by ack (Deacon) on Jan 29, 2009 at 16:17 UTC
Re^6: Hard syntax error or disambiguable parsing? by pobocks (Chaplain) on Jan 29, 2009 at 06:48 UTC
Re^7: Hard syntax error or disambiguable parsing? by GrandFather (Saint) on Jan 29, 2009 at 06:51 UTC
Re^4: Hard syntax error or disambiguable parsing? by Marshall (Canon) on Jan 30, 2009 at 19:21 UTC
I for one applaud your statement about clarity! I see a lot of code on Monks that uses obscure features of Perl when they aren't necessary. I also see a massive fascination with $#list. I don't understand why that is! The scalar value of @list does everything I need. One of the magic things about Perl is the ability to iterate over a list without knowing or caring about the "last index" or how many things are even in the list! I always use foreach(@list){} instead of for(@list){}. A "C" style "for loop" is a rare duck in Perl (although seldom doesn't mean never). Even though "for" and "foreach" are equivalent in this case, foreach my $variable (@list){} is more clear. HORRAY!	[reply]


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