Re^2: What is the best way to compare variables so that different types are non-equal?

I don't know why you crossed out "compiles".

>perl -Mre=debug -e"qr/a/"
Compiling REx "a"
Final program:
   1: EXACT <a> (3)
   3: END (0)
anchored "a" at 0 (checking anchored isall) minlen 1
Freeing REx: "a"
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Re^3: What is the best way to compare variables so that different types are non-equal? by BrowserUk (Patriarch) on Jul 19, 2009 at 16:21 UTC
I don't know why you crossed out "compiles". Because the docs I quoted used the term 'normalises'. Can they be both compiled and normalised? Can they be normalised and not compiled or vice versa? Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error. "Science is about questioning the status quo. Questioning authority". In the absence of evidence, opinion is indistinguishable from prejudice. RIP PCW	[reply]
Re^4: What is the best way to compare variables so that different types are non-equal? by ikegami (Patriarch) on Jul 19, 2009 at 16:25 UTC
Can they be both compiled and normalised? Yes. I didn't mean to imply what you said was wrong. Can they be normalised and not compiled or vice versa? No. `qr//` always compiles. `qr//` always returns the regex flags when used as as string.	[reply] [d/l] [select]


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