http://www.perlmonks.org?node_id=827094

While I'm still able to remember, I list below the other new (albeit unsuccessful) Ruby solutions I found while searching for the elusive 111 stroker. It's possible I've missed something and one of these attempts might be transformed from a loser into a winner.

The following solutions are all of a similar form to the original 111 stroker, namely:

```r=*\$<;'XXXXXXXXXXXX'.each_byte{|i|\$><<"%#{327%i/9}c"%
'hxmo'[(i-r.to_i)%12/~i^~r[3,2].to_i/5%i%12/11]+\$/*(i/85)}
where XXXXXXXXXXXX above is a string with ord values 120, 47, 253, 22, 194, 21, 183, 44, 196, 55, 125, 246. For clarity below, I show only the 'hxmo'[expr] expressions:
```'hxmo'[(i-r.to_i)%12/~i^~r[3,2].to_i/5%i%12/11]
'ohmx'[1>>(i-r.to_i)%12^2&2<<i%12-r[3,2].to_i/5]
'hxmo'[(i-r.to_i)%12/-i^0**(i%12^r[3,2].to_i/5)]
'mxho'[1>>(i-r.to_i)%12^(i%12^r[3,2].to_i/5)/-i]
'mxho'[(r[3,2].to_i/5-i)%12/-i^1>>(r.to_i-i)%12]
'hxmo'[(i-r.to_i)%12/-i^1>>(2*r[3]+r[4]/53-i)%12]
'mxho'[(2*r[3]+r[4]/53-i)%12/-i^1>>(i-r.to_i)%12]
'ohmx'[1>>(i-r.to_i)%12^(i%12==r[3,2].to_i/5).id]

And here are some other random attempts:

```r=*\$<;'XXXXXXXXXXXX'.each_byte{|i|printf"%*c"+\$/*(i/85),
327%i/9,'hxmo'[(i-r.to_i)%12/~i^~r[3,2].to_i/5%i%12/11]}

r=*\$<;'XXXXXXXXXXXX'.each_byte{|i|\$><<" "*(318%i/9)+
'hxmo'[(i-r.to_i)%12/~i^~r[3,2].to_i/5%i%12/11,1]+\$/*(i/85)}

/:/!~gets;'XXXXXXXXXXXX'.each_byte{|i|\$><<"%#{327%i/9}c"%
'hxmo'[(i-\$_.to_i)%12/~i^~\$'.to_i/5%i%12/11]+\$/*(i/85)}

r=*\$<;\$><<"%#{327%J/9}c"%'hxmo'[~r[3,2].to_i/5%J%12/11^
(J-r.to_i)%12/~J]+\$/*(J/85)while J='ohXXXXXXXXXXXX'[\$.+=1]

r=*\$<;loop{i="hmXXXXXXXXXXXX"[\$.+=1];\$><<"%#{327%i/9}c"%
'hxmo'[(i-r.to_i)%12/~i^~r[3,2].to_i/5%i%12/11]+\$/*(i/85)}

r=*\$<;'XXXXXXXXXXXX'.each_byte{|i|\$><<"%*c"%[327%i/9,
(i%12==r.to_i%12??x:?o)&(i%12==r[3,2].to_i/5??}:?o)]+\$/*(i/85)}

gets=~/:/;'XXXXXXXXXXXX'.each_byte{|i|print" "*(318%i/9),
(111+(i%12==\$_.to_i%12?9:0)&111+(i%12==\$'.to_i/5?14:0)).chr,\$/*(i/85)}