Re: assigning regex matches to variables

Change my $digits = $string2 =~ /(\d)+/; to my ($digits) = $string2 =~ /(\d)+/; and it will work. The parens changes the assingment from scalar to list context.

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Re^2: assigning regex matches to variables by JavaFan (Canon) on May 28, 2011 at 20:22 UTC
Context is one thing, but the regexp needs to be fixed as well. It ought to be `/(\d+)/`, with the plus inside the parenthesis.	[reply] [d/l]
Re^2: assigning regex matches to variables by genghis (Novice) on May 28, 2011 at 20:26 UTC
Couldn't get that to work. Also tried `my @digits = $string2 =~ /(\d)+/;` which didn't work either. I guess I'm generally confused about whether the =~ operator actually assigns the result of the search; i.e. whether `$var =~ /some_regex/;` changes the value of $var.	[reply] [d/l] [select]
Re^3: assigning regex matches to variables by jwkrahn (Abbot) on May 28, 2011 at 20:33 UTC
`$var =~ /some_regex/;` does not change the value of `$var`, it just searches through `$var` for the pattern `/some_regex/`.	[reply] [d/l] [select]


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