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how about if you work the problem the other way.
Base 2 Base 10 ---------------------------------------------- .0001 == 0/2 + 0/4 + 0/8 + 1/16 == .0625 .0010 == 0/2 + 0/4 + 1/8 + 0/16 == .125 .0011 == 0/2 + 0/4 + 1/8 + 1/16 == .1875 .0100 == 0/2 + 1/4 + 0/8 + 0/16 == .25 .0101 == 0/2 + 1/4 + 0/8 + 1/16 == .3125 .0110 == 0/2 + 1/4 + 1/8 + 0/16 == .375 .0111 == 0/2 + 1/4 + 1/8 + 1/16 == .4375 .1000 == 1/2 + 0/4 + 0/8 + 0/16 == .5 .1001 == 1/2 + 0/4 + 0/8 + 1/16 == .5625 .1010 == 1/2 + 0/4 + 1/8 + 0/16 == .625 .1011 == 1/2 + 0/4 + 1/8 + 1/16 == .6875 .1100 == 1/2 + 1/4 + 0/8 + 0/16 == .74 .1101 == 1/2 + 1/4 + 0/8 + 1/16 == .8125 .1110 == 1/2 + 1/4 + 1/8 + 0/16 == .875 .1111 == 1/2 + 1/4 + 1/8 + 1/16 == .9375 has you can see there are gaps in between the decimal numbers. The more accurate you want to get the more digits in the base 2 numbers you need. Assuming that you're working with a computer that has 32 bit registers you can only store a finite number so you may not always have enough bits to represent the fraction you want. jjdraco learning Perl one statement at a time. In reply to Re: Re: Still puzzled by floats
by jjdraco
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