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Interesting. I wrote my own that does pretty much the same thing, but in a different way (I only use one hash, so I suspect it will use less memory (but see response below for the final word)).

#! /usr/bin/perl -w use strict; use File::Find; use Digest::MD5; my %digest; my $total_bytes = 0; my $dups = 0; sub wanted { return unless -f $_; my $bytes = -s _; return unless $bytes; if( !open IN, $_ ) { print "Cannot open $_ for input: $!\n"; return; } my $md5 = Digest::MD5->new; my $d = $md5->addfile( *IN )->digest; close IN; if( defined $digest{$d} ) { print "$bytes\t$digest{$d}\t$File::Find::name\n"; $total_bytes += $bytes; ++$dups; } else { $digest{$d} = $File::Find::name; } } foreach my $d ( @ARGV ) { print "=== directory $d\n"; find \&wanted, $d; } printf "Statistics: Duplicates: %12d Bytes: %12d KBytes: %12d MBytes: %12d GBytes: %12d\n", $dups, $total_bytes, $total_bytes / (1024**1), $total_bytes / (1024**2), $total_bytes / (1024**3);

It is very verbose, but that's because I pipe the output into something that can be handed off to users in a spreadsheet so that they can do their own housekeeping (2Gb of duplicates in 45Go of files...).

BTW, you can also save a squidgin of memory by using the digest() method, rather than the hexdigest() method, since the value is not intended for human consumption.


In reply to Re: Find duplicate files. by grinder
in thread Find duplicate files. by salvadors

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