exec & system

[dideod.yang]

Hi monks. I need your idea to achieve my script.. I understand difference between exec and system. LOCAL is my local command in my linux. My goal is when LOCAL command fail, then script try again command. How can I do that? below script, each case has limit point.. Please help me.

#LOCAL: local command
#case 1 # when LOCAL failed script die
exec "LOCAL";
print "success";

#case 2 #when LOCAL failed but print suceess
system "LOCAL";
print "success";

[kevbot]

Hello dideod.yang,

I do not understand how exec can help here, since the documentation states that it never returns. The system command seems more appropriate. Here is an example to help illustrate how you can use the system command to execute your command and to check its exit status. When placed inside the while loop, you can keep executing the shell script until you get the successful exit status of 0. I made my own shell script to randomly generate an exit status of 0 or 1. I show that below as well.

#!/usr/bin/env perl

use strict;
use warnings;

my $status = 1;

# Keep trying rand_exit.sh until the exit status is zero
while( $status ){
    $status = system "./rand_exit.sh";
    print "Still trying\n";
    sleep 1;
}
print "Success!\n";
exit;

rand_exit.sh

#!/usr/bin/env bash

BINARY=2
T=1
number=$RANDOM

let "number %= $BINARY"
if [ "$number" -eq $T ]
then
 exit 1; 
else
 exit 0;
fi

The code will take a random number of iterations to complete. The output will look something like this,

Still trying
Still trying
Still trying
Success!