in reply to Re: Re: quick question about parenthesis and regular expressions
in thread quick question about parenthesis and regular expressions
Ummm, I have no problem doing the substitution using the code supplied:
$line = "She was very absorbed in her homework."; $word = "absorb"; print STDOUT "Line: $line\n"; $line =~ s/($word(?:s|ed))/<b>$1<\/b>/igm; print STDOUT "New Line: $line\n"; print STDOUT "\$1 contains: $1\n";
Of course, I might consider changing it slightly to read:
$line =~ s/\b(${word}(?:s|ed)?)\b/<b>$1<\/b>/igm;
However, I did just discover that there is something more going on here, because while the original (without the \b) does set something in $1, my change doesn't (despite doing the substitution properly).
And finally, if you're just doing a match why are you using s///?
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Re... quick question about parentheses and regular expressions
by Roy Johnson (Monsignor) on Nov 04, 2003 at 18:08 UTC | |
Re: Re: Re: Re: quick question about parenthesis and regular expressions
by tilly (Archbishop) on Nov 04, 2003 at 18:49 UTC |
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