Re: Efficient way to replace a set of values with another set of values

[Cody Fendant]

How about this:

$str = q{
1. This is just a sample.
2. This is to check 
3. How a set of values 
4. can be replaced by another 
5. set of values and that too 
6. in the most efficient way.
};

$str =~ s/^(\d)/chr($1+96)/meg;

print $str;

### prints:
a. This is just a sample.
b. This is to check 
c. How a set of values 
d. can be replaced by another 
e. set of values and that too 
f. in the most efficient way.

[Arunbear]

Command line version:

perl -pi -e 's/^(\d)/chr($1+96)/e' myfile

[space_monk]

Parent beat me to the one line solution, but perhaps a minor mod may be needed; I suspect that the OP may have numbers larger than just 1-6, so perhaps:

perl -pi -e 's/^(\d+)/chr($1+96)/e' myfile

[roboticus]

space_monk:

OK, your solution is a bit better .... at least until you get to "27. This is a really long list!".

;^D

...roboticus

When your only tool is a hammer, all problems look like your thumb.