### Re: Re: Re: Anyone use "xor" in conditionals?

by exussum0 (Vicar)
 on Jul 14, 2003 at 16:29 UTC ( #274035=note: print w/replies, xml ) Need Help??

in reply to Re: Re: Anyone use "xor" in conditionals?
in thread Anyone use "xor" in conditionals?

Can you say that the internals of perl don't do the optimizations on user behalf? I'd hope that perl automatically thows out the expression w/o doing it fully if it finds out it's dead in the middle.

btw, your way is for those who don't have the concept, or truth table, memorized and reproduce it w/o thinking. Nothing wrong w/ it though.

Regardless, xor isn't something that is as easily applicapble such as, the plus operator or just the and operator.

Certain tools, for certain situations.

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Re: Re: Re: Re: Anyone use "xor" in conditionals?
by Excalibor (Pilgrim) on Jul 14, 2003 at 17:08 UTC

I am sure the Perl internals don't optimize a lot of things, specially in examples like Abigail showed us how to reduce the number of % operations by a careful use of user shortcuts (instead of depending in Perls shortcut for logical operators)

Well, actually, if I recall well, that's exactly the truth table for XOR:

```A B  XOR
0 0   0
1 0   1
0 1   1
1 1   0

Ie. Either A is true and B is false, or B is true and it's A which is false. This form has the advantage over the other one than in the first part is true (ie. A and not B) there's no need to compute the second one (2 calculations, 1 per proposition). The first proposed form, which is a description of 'exclusive or' (ie. either A or B but not both at once) forces the evaluation of both parts (ie. Once proposition A and again A and proposition B to test the second one, which makes it 3. In the case it's neither A or B it shortcircuits sooner, that's right, and if A is false, then propositions A and B must be tested twice in both cases: it's a matter of taste, I guess).

And obviously I agree with you that XOR is pretty much more specialized than, say AND or PLUS...

OTOH, I'd love for Perl to implement a fast NAND (which by itself creates a complete Boolean algebra). BTW, nand doesn't make expressions easier to read, but much faster as it would shorcircuit much sooner in most cases...

Best regards,

--
our \$Perl6 is Fantastic;

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