Re: fast string parser: regex versus substr

[Abigail-II]

Well, at least one of the approaches is incorrect. I uncommented the warnings, turned them into prints and added the following to your program:

dosubstr;
print "---\n";
doregex;

Running your program gives me:

A12345 RELEASE 
  
A1 2345RELEASEA12345 
FTOP DD_BUIL+ 
  
FT OPDD_REKL+FTOP 
FTOP DD_PLAN+ 
  
FT OPDD_REKL+FTOP 
---

Abigail