How to view all files in the directory using CGI

[ArmandoG]

Hello !! I am not going to lie to you guys, I have no Idea on how to do this
being honest, I need to do a script that it will show me a specific directory (c:/file/out) in a webpage and that all the files be a link to be able to download them. Please is not for some homework

Thanks

[jZed]

Which part are you having problems with - reading the directory? looping through the files? forming the correct URL from the filename? creating the html link with a template? displaying the web page?

Whether it's homework or not, if you don't try something and tell us where you are stuck, we can't help.

[ArmandoG]

you are absolutly right! :o), sorry if did not read you sooner
I have been working on some code, as far as now it show me only on /cgi-bin/ folder the file I want, but I like to change it to something like a server folder but for know just C:/files/err folder for now, I can display it on the Firefox browser, but if I click a link to the file is giving me an error, but i want a dialog to say if you open it or save it to disk. heres the code :

#!c:/perl/bin/perl.exe

use strict;
use CGI;

my $list = new CGI;

my $fileDir = "./";
my @files;

opendir DIR, "$fileDir" or die "Can't open $fileDir $!";
    @files = grep { /\.(?:txt|err|csv)$/i } readdir DIR;
closedir DIR;

print $list->header("text/html"),
      $list->start_html("Archivos in $fileDir"),
      $list->p("Estos son los archivos de $fileDir");

foreach my $file (@files) {
    print $list->p(
            $list->a({-href=>$file},
            $file)
            );
    
}

print $list->end_html;

[jZed]

If your only problem is reading the right directory,then all you need to do is change the line that sets $filedir to:

my $fileDir ='c:/file/out';

You'll also need to figure out what relation there is between that directory and a reachable URL path.