I just realized we can reduce my original packed 95-stroker:
map$c[$_*=.52,5.5-4.7*cos][8+7.4*sin]=($`%12^$_?o:x)&($'/+5^$
a.$_?o:v125),0..s//<>/e./:/;print"@$_\n"for@c
by two strokes:
map$c[$_*=.52,5.5-4.7*cos][8+7.4*sin]=($`%12^$_?o:x)&($'/5^$_
?o:v125),0..s//<>/e./:/;print"@$_\n"for@c#```
As you can see from the table below, the "?"
character, by pure fluke, is two before "A" in
the ASCII table:
| ord | pack | len | chr |
|---|
| 63 | 31 | | ? |
| 64 | 32 | | @ |
| 65 | 33 | 45 | A |
So we can hijack pack's "?" length byte
as part of our ternary expression!
Note that we padded the source program with #``` at the end
to keep its length at 45, the required multiple of four.
