in reply to Re^2: hash parameter question
in thread hash parameter question
Nope. $_ contains a string. A key from %users; which is presumably a username. Your suggestion will therefore not work.
Had PerlHeathen written:
foreach(values %users) { my %user=$_; my $pw=getpwnam($user{uname}); my $homedir=$pw->dir; }
(note the use of values) then $_ would be a reference to a hash and then your solution would make the code work.
For example:
foreach(values %users) { my %user=%$_; my $pw=getpwnam($user{uname}); my $homedir=$pw->dir; }
It is likely that this is what PerlHeathen was trying to write in the first place.
jarich
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