Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:
Hi all! At work, I'm writing a script that uses a configuration file of strings that are converted to regular expressions. I have my script working for matching, but it breaks for substitution. For example, the string to match to might look like
$lhs = (\d*?)-(.*?)-(.*)and the right hand side (for substitution looks like:
$rhs = $1$2$3I'm using the code likes this:
$var =~ s/$lhs/$rhs/eeIf I run it like above, I get an error message:
Scalar found where operator expected at (eval 1) line 1, near "$1$" (Missing operator before $?) Scalar found where operator expected at (eval 1) line 1, near "$2$" (Missing operator before $?)
I've also tried with a single "e" or no "e"s at all, and just get this for the value of $var: $1$2$3
For the test case that I'm passing into this regular expression, it is matching properly and all the capture groups are capturing ( I had it print out the values of $1, $2, $3 and it gave me the expected output correctly )
This is running on a server at work that has Perl v5.8.8 installed on it. Unfortunately, the decision to upgrade it is not mine, although discussions have been started once I raised it as a concern. Is the age of this Perl install the problem, or am I missing something else?
Thanks in advance for any assistance!
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Re: "ee" in Regular Expression: version issue?
by Kenosis (Priest) on Dec 03, 2012 at 19:52 UTC | |
by kennethk (Abbot) on Dec 03, 2012 at 20:23 UTC | |
by Kenosis (Priest) on Dec 03, 2012 at 20:32 UTC | |
Re: "ee" in Regular Expression: version issue?
by ikegami (Patriarch) on Dec 04, 2012 at 11:38 UTC | |
s/RegEx/substitutions/: Variable interpolation and when to use /e - modifiers
by LanX (Saint) on Dec 04, 2012 at 18:58 UTC | |
Re: "ee" in Regular Expression: version issue?
by Anonymous Monk on Dec 03, 2012 at 19:32 UTC |