Re^2: Hash of arrays

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Re^3: Hash of arrays by CountZero (Bishop) on Dec 28, 2012 at 07:32 UTC
How can we know why things get printed twice? The code you showed does not even have a `print` statement! I am pushing a user name and an array of AD groups for that user name into a hash of arrays: Code: `push (@{$newgrouphash{"$newdn"} },"$newgroup")` You are not pushing an array of AD groups into a HoA. You are pushing the stringified version of a scalar into your HoA. For a start, drop all the double quotes around your variables. They serve no purpose. Then check whether `$newgroup` indeed contains a reference to your array of AD groups. And finally show us the code you use to output this data. CountZero A program should be light and agile, its subroutines connected like a string of pearls. The spirit and intent of the program should be retained throughout. There should be neither too little or too much, neither needless loops nor useless variables, neither lack of structure nor overwhelming rigidity." - The Tao of Programming, 4.1 - Geoffrey James My blog: Imperial Deltronics	[reply] [d/l] [select]
Re^4: Hash of arrays by perlloz (Initiate) on Dec 28, 2012 at 07:45 UTC
Sorry, new here, I used the print statements from the previous posters suggestions. The actual data being pushed into the HOA is a lot of code and is an AD query so it wouldn't compile. What I end up with is a key of Bob and an array containing groups: domain users, testing, server team etc push (@{$newgrouphash{"$newdn"} },"$newgroup"); foreach $newdn (sort keys %newgrouphash ) { print "Name:$newdn\n\t"; foreach $group ( sort @{$newgrouphash{$newdn}} ) { + if (!($group =~ /CN=Domain Users/i)) { # print "$group, "; + $res = `dsmod group $group -rmmbr \"$newdn\"`; + print "$res\n"; [download]	[reply] [d/l]
Re^5: Hash of arrays by Anonymous Monk on Dec 28, 2012 at 07:47 UTC
Data Dumper Data Dumper Dumps the Data so the problem of accessing the HoA is seperated from populating the HoA	[reply]
Re^3: Hash of arrays by NetWallah (Canon) on Dec 28, 2012 at 07:53 UTC
As others have suggested, please post the code where you do the "push", and the "print". I re-read your statement: I am pushing a user name and an array of AD groups for that user name into a hash of arrays So -it sounds like you are pushing both the NAME and the GROUP into the hash value. This is in addition to the name being in the Key. If this is the case, it would indeed explain the name coming out twice, since you (or at least my posted code) prints the key and value. Anyway - this discussion would be a lot less abstract and hypothetical, if you posted your actual code. In it's absence, interest in assisting you is rapidly waning. "By three methods we may learn wisdom: First, by reflection, which is noblest; Second, by imitation, which is easiest; and third by experience, which is the bitterest." -Confucius	[reply]
Re^4: Hash of arrays by perlloz (Initiate) on Dec 28, 2012 at 07:56 UTC
sorry, trying to post the code but keep getting a duplicate post warning. Can you see it?	[reply]
Re^5: Hash of arrays by ww (Archbishop) on Dec 28, 2012 at 12:56 UTC
One way to avoid that is to go back to the top of this thread (your original post) and edit it -- with careful attention to retaining --behind a strikeout -- anything you're deleting, and with prominent notes marking what you add.	[reply]
Re^4: Hash of arrays by perlloz (Initiate) on Dec 28, 2012 at 08:05 UTC
Hi, I am posting the code but don't see it displaying. This isn't through a lack of hiding code from you I am just battling to find my way around the site. Please be patient until I get the hang of it.	[reply]
Re^4: Hash of arrays by perlloz (Initiate) on Dec 28, 2012 at 08:25 UTC
have you managed to get my code?	[reply]
Re^3: Hash of arrays by Anonymous Monk on Dec 28, 2012 at 07:32 UTC
Thanks, I still get this result: Name: Name:CN=test123,OU= etc etc The group prints fine Funny :) If you want help, you'll need to provide sample data (as in Data::Dump, Data::Dumper ... ) as Basic debugging checklist explains	[reply]


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