Re: Using an array element as a loop iterator

in reply to Using an array element as a loop iterator

I suppose you didn't write what you thought you were writing. First, square brackets are not used to make a list, like in python, but an arrayref, which is only one element. So @a contains only one element which is [1,2,3]. @b on the other is indeed an array.

Could you write what you were intending to in python? If I translate your code it would be something like:

for each element in @b
   $a[1] = element
   print $a[1]
done
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If you want to use the indexes in @a to go through @b you can either use a slice (EDIT: not splice ...) of @b :

@a = (1,2,3);
@b = (2,4,6,7);
print for @b[@a]; # print for elements of @b with indexes in @a
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Or loop through @a :

@a = (1,2,3);
@b = (2,4,6,7);
for $i (@a)
{
   print $b[$i];
}
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NB: As for the error, I guess in for VAR (LIST) VAR can only be a variable, not any lvalue.

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