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Re: How can I upload a file using HTTP POST with Content-Type=multipart/form-data?

by merlyn (Sage)
on Sep 18, 2000 at 08:35 UTC ( [id://32918]=note: print w/replies, xml ) Need Help??


in reply to How can I upload a file using HTTP POST with Content-Type=multipart/form-data?

I can't tell if you mean "write the server-side code to handle the uploaded file" or "write the client-side code to simulate what a browser does to upload a file".

If the former, use CGI.pm:

CREATING A FILE UPLOAD FIELD print $query->filefield(-name=>'uploaded_file', -default=>'starting value', -size=>50, -maxlength=>80); -or- print $query->filefield('uploaded_file','starting value',50 +,80); filefield() will return a file upload field for Netscape 2.0 browsers. In order to take full advantage of this you must use the new multipart encoding scheme for the form. You can do this either by calling start_form() with an encoding type of &CGI::MULTIPART, or by calling the new method start_multipart_form() instead of vanilla start_form(). Parameters 1. The first parameter is the required name for the field (-name). 2. The optional second parameter is the starting value for the field contents to be used as the default file name (-default). For security reasons, browsers don't pay any attention to this field, and so the starting value will always be blank. Worse, the field loses its "sticky" behav- ior and forgets its previous contents. The starting value field is called for in the HTML specification, however, and possibly some browser will eventually provide support for it. 3. The optional third parameter is the size of the field in characters (-size). 4. The optional fourth parameter is the maximum number of characters the field will accept (-maxlength). When the form is processed, you can retrieve the entered filename by calling param(): $filename = $query->param('uploaded_file'); Different browsers will return slightly different things for the name. Some browsers return the filename only. Others return the full path to the file, using the path conventions of the user's machine. Regardless, the name returned is always the name of the file on the user's machine, and is unrelated to the name of the temporary file that CGI.pm creates during upload spooling (see below). The filename returned is also a file handle. You can read the contents of the file using standard Perl file reading calls: # Read a text file and print it out while (<$filename>) { print; } # Copy a binary file to somewhere safe open (OUTFILE,">>/usr/local/web/users/feedback"); while ($bytesread=read($filename,$buffer,1024)) { print OUTFILE $buffer; }

If the latter, use HTTP::Request::Common:

The POST method also supports the `multi- part/form-data' content used for Form-based File Upload as specified in RFC 1867. You trigger this content format by specifying a content type of `'form-data'' as one of the request headers. If one of the values in the $form_ref is an array reference, then it is treated as a file part specification with the following interpretation: [ $file, $filename, Header => Value... ] The first value in the array ($file) is the name of a file to open. This file will be read and its content placed in the request. The routine will croak if the file can't be opened. Use an `undef' as $file value if you want to specify the content directly. The $filename is the filename to report in the request. If this value is undefined, then the basename of the $file will be used. You can specify an empty string as $filename if you don't want any filename in the request.

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