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Looking again I see you're right.

But still, rather than invoking the regex engine 50,000 times, better to search for the position of the 50,000th ! and then replace in one pass.

#! perl -slw use strict; use Time::HiRes qw[ time ]; my $s = '1234!' x 55e3; my $start = time; my( $p, $c ) = ( 0, 50e3 ); 1 while --$c and $p = 1+ index $s, '!', $p; substr( $s, 0, $p ) =~ tr[!][\n]; printf "Took %f seconds\n", time() - $start; __END__ C:\test>junk71;; Took 0.011771 seconds C:\test>junk71;; Took 0.009690 seconds

That could probably be sped up with a binary chop for the position, but it hardly seems worth it.


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In reply to Re^3: Fast Replacement (0.01 seconds) by BrowserUk
in thread Fast Replacement by sathishselvam

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