The problem is that Perl doesn't abstract the concept of appending for its various containers (scalars, arrays, and hashes), because Perl isn't inherently OO. I don't know if Perl 6 is going this route, where you could say:
$foo.append($bar);
@foo.append(@bar);
%foo.append(%bar);
And in the same vein, perhaps:
$foo.prepend($bar);
@foo.prepend(@bar);
%foo.prepend(%bar);
In recent Perls, we can write this as:
# append($x, $y) appends $y to $x
# etc.
# prepend() left as a simple exercise to the reader
sub append (\[$@%]\[$@%]) {
use Scalar::Util 'reftype';
use Carp qw( croak );
my ($l, $lt, $r, $rt) = map { $_, reftype($_) } @_;
if ($lt eq $rt) {
if ($lt eq 'SCALAR') {
$$l .= $$r;
}
elsif ($lt eq 'ARRAY') {
push @$l, @$r;
}
elsif ($lt eq 'HASH') {
@$l{keys %$r} = values %$r;
}
else {
croak "append($lt,$rt) not implemented";
}
}
else {
croak "append($lt,$rt) not implemented";
}
}
I'd expect friction coming from the "what does append/prepend mean for hashes?" faction, but I'd say it's a matter of precedence. Appending to a hash, when there are duplicate keys, uses the new values, and prepending would use the old values.
_____________________________________________________
Jeff
japhy Pinyan,
P.L., P.M., P.O.D, X.S.:
Perl,
regex,
and
perl
hacker
How can we ever be the sold short or the cheated, we who for every service have long ago been overpaid? ~~ Meister Eckhart
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